5x+x^2-(x-3x^2)=

Solution for 5x+x^2-(x-3x^2)= equation:

5x+x^2-(x-3x^2)=

We move all terms to the left:

5x+x^2-(x-3x^2)-()=0

We add all the numbers together, and all the variables

x^2-(x-3x^2)+5x=0

We get rid of parentheses

x^2+3x^2-x+5x=0

We add all the numbers together, and all the variables

4x^2+4x=0

a = 4; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·4·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*4}=\frac{-8}{8}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*4}=\frac{0}{8}
=0
$